calculate hexadecimal number for given numbet

#include<stdio.h>
#include<conio.h>
main()
{
int a[10],i,b,j,c;
char h[16]={'0','1','2','3','4','5','6','7','8','9','A','B','C','D','E','F'};
clrscr();
printf("enter number");
scanf("%d",&b);
for(i=0;b>0;i++)
{
a[i]=b%16;
b=b/16;
}
//if(h[i]>9)
//{
//h[i]={'A','B','C','D','E','F'};
printf("hexadecimal number is:");
for(i--;i>=0;i--)
{
printf("%c",h[a[i]]);
}
getch();
return 0;
}